And again, since there space 5 "20s" in 100, then 5 x 4 = 20 numbers divsible by 5.

You are watching: How many numbers between 1 and 100 (inclusive) are divisible by 9 or 4

However, we need to subtract out the numbers divisible by both 4 and 5 to prevent "double counting."

These would certainly be 20, 40, 60, 80 and 100.

Thus, we have 25 + 20 - 5 = 40 numbers divisible by 4 or 5 native 1-100, inclusive.

CPhill May 20, 2014

#1
+121059
+8

Let"s think around it in teams of 20.

Note, native 1 to 20, 5 numbers room divisible by 4.....4, 8, 12, 16, 20

And since there space 5 "20s" in 100, climate 5 X 5 = 25 number divisible by 4.

Likewise, there are 4 numbers divisible by 5.......5 , 10 , 15 , 20

And again, due to the fact that there are 5 "20s" in 100, then 5 x 4 = 20 numbers divsible by 5.

However, we have to subtract the end the number divisible by both 4 and also 5 to stop "double counting."

These would certainly be 20, 40, 60, 80 and also 100.

Thus, we have actually 25 + 20 - 5 = 40 numbers divisible by 4 or 5 from 1-100, inclusive.

CPhill May 20, 2014

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