Since the question is a little bit ambiguous, I will certainly assume that you"re handling three unique sets of quantum numbers.

In addition to this, ns will likewise assume that you"re fairly familiar v quantum numbers, so i won"t go into too lot details about what every represents.

#1^"st"# set # -> n=2#

The principal quantum number, #n#, tells you the power level on which an electron resides. In stimulate to be able to determine how countless electrons can share this worth of #n#, you should determine exactly how numerous orbitals you have in this power level.

The number of orbitals you acquire per energy level have the right to be discovered using the equation

#color(blue)("no. Of orbitals" = n^2)#

Since each orbital can hold amaximum of two electrons, it adheres to that as countless as

#color(blue)("no. That electrons" = 2n^2)#

In this case, the 2nd energy level stop a full of

#"no. The orbitals" = n^2 = 2^2 = 4#

orbitals. Therefore, a best of

#"no. The electrons" = 2 * 4 = 8#

electrons have the right to share the quantum number #n=2#.

#2^"nd"# set #-> n=4, l=3#

This time, girlfriend are provided both the energy level, #n=4#, and also the subshell, #l=3#, on i beg your pardon the electrons reside.

Now, the subshell is given by the angular inert quantum number, #l#, which deserve to take values varying from #0# to #n-1#.

#l=0 -># the s-subshell#l=1 -># the p-subshell#l=2 -># the d-subshell#l=3 -># the f-subshell

Now, the number of orbitals you obtain per subshell is offered by the magnetic quantum number, #m_l#, which in this situation can it is in

#m_l = -l, ..., -1, 0, 1, ..., +l#

#m_l = -3; -2; -1; 0; 1; 2; 3#

So, the f-subshell can hold complete of seven orbitals, which means that you have actually a best of

#"no. The electrons" = 2 * 7 = 14#

electrons that have the right to share these 2 quantum numbers, #n=4# and #l=3#.

#3^"rd"# set #-> n=6, l=2, m_l = -1#

This time, you are provided the power level, #n=6#, the subshell, #l=2#, and also the exact orbital, #m_l = 1#, in which the electrons reside.

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Since you recognize the exact orbital, it follows that just two electrons deserve to share these 3 quantum numbers, one having actually spin-up, #m_s = +1/2#, and also the other having spin-down, #m_s = -1/2#.