based on an experiment, a systems that consisted of $ceCu^2+$ formed a precipitate v $ceNaOH$. Is this exactly how you write the equation?

$$ce2NaOH + Cu^2+ -> Cu(OH)2 + 2Na+$$

On the experiment: solution A is blended with NaOH (solution turn white). Making use of a fire test equipment A is color green. Ns figured systems A has $ceCu^2+$ ion.

You are watching: Copper (ii) sulfate and sodium hydroxide net ionic equation



Yes, the reaction is correct however it might be preferable come either include all or no spectator ions.Use one of two people a network ionic equations (omit the Na+), molecular equation (include the copper compound full) or finish ionic equation.

For example, if the compound is copper sulphate the equations would be (without states)

Net ionic$$ceCu^2++ce2OH^-->Cu(OH)_2$$Molecular equation$$ceCuSO_4+ce2NaOH->Cu(OH)_2+ceNa_2SO_4$$Complete Ionic Equation$$ceCu^2+ +SO_4^2-+ce2Na^+ +2OH^-->Cu(OH)_2+ce2Na^+ +SO_4^2-$$


In the situation where girlfriend don"t recognize what copper link it is, usage a net ionic equation. As a next note, copper hydroxide is not white. You might want to inspect your calculations.

If you"re wonder what it is, inspect what various other compounds will certainly emit green.

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edited Dec 19 "16 in ~ 1:08
reply Dec 19 "16 at 1:03

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